(0,25*t^2)-(5*t)=0

Solution for (0,25*t^2)-(5*t)=0 equation:

(0.25t^2)-(5t)=0

We add all the numbers together, and all the variables

-5t+(0.25t^2)=0

We get rid of parentheses

0.25t^2-5t=0

a = 0.25; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·0.25·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*0.25}=\frac{0}{0.5}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*0.25}=\frac{10}{0.5}
=20
$